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A compound has an empirical formula of C2H4O and a molar mass of 88 grams per mole. What is the molecular formula of this compound?

AdamTaurus  Oct 17, 2017
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A compound's empirical formula tells you the smallest whole number ratio that exists between the elements that make up a compound.

In your case, the unknown compound has an empirical formula of C2H4O, which means that it contains carbon, C, hydrogen, H, and oxygen, O, in a 2:4:1 ratio.

In other words, one mole of this compound will contain carbon, hydrogen, and oxygen in a 2:4:1 mole ratio.

All you have to do now is determine the mass of the empirical formula and compare it with the molar mass of the compound. You will have

2×12.011 g mol−1+4×1.00794 g mol−1+1×15.9994 g mol−1=44.053 g mol−1

The molar mass of the compound essentially tells you the mass of one mole of the compound. This means that you will have

44.053g mol−1×n=88g mol−1

Rearrange to get

n=88 / 44.053=1.9976≈2

Therefore, the molecular formula of the compound, which tells you the exact number of atoms of each element present in one molecule of the compound, will be:

(C2H4O)2 =C4H8O2

Guest Oct 17, 2017
edited by Guest  Oct 17, 2017
 #2
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You could have posted this link

 

https://socratic.org/questions/what-is-the-molecular-formula-for-a-compound-with-an-empirical-formula-of-c2h4o-

 

It’s neater than your slop copy you plagiarized and posted here. frown

GingerAle  Oct 17, 2017

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