Help PLEASE!

Quote:

A room has 32 columns, each 13 feet high and 2 feet in circumference. How much ribbon do I need to wrap each column 8 times?

how wide is the ribbon?

Unfortunately I don't recall that being in the original question. I would guess just normal size.

Quote:

each 13 feet high and 2 feet in circumference. How much ribbon do I need to wrap each column 8 times?

normal size... all right whatever, let it be an inch.

basically the idea is that you have (13*12)/1 loops of ribbon each 1 circumference long to wrap the column once.

so for 8 times you get

8 * (13*12)/1 * 2 = 416 feet

if the ribbon was 2 inches wide you'd need 208 feet.

I get this when I type in your answer, which thank you by the way. "Sorry that's not correct. To simplify the problem, imagine that the wrapped post is cut lengthwise. When the post is pressed flat, the ribbon lies in straight segments, each of which is the hypotenuse of a right triangle." Also forgot to include the fact that the columns are cylindrical, if that matters or helps.

So I went at the problem that you just want to go around the columns 8 times not cover them.
What you would do is find the circumfrence of the columns which is 2 multiply that by the number of times you want it wrapped, then multiply by the number of columns in the room which is 32

(2 feet * 8) * 32 columns = 512 feet