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a metallurgist has an alloy with 10% titanium and an alloy with 20% titanium. he needs 100 grams of an alloy with 16% titanium. how much of each alloy should be mixed to attain the 100 grams of alloy with 16% titanium?

 Aug 20, 2020
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Let the number of grams of 10%titanium needed=T
Then, the number of grams of 20% titanium needed =100 - T
0.1T + 0.2[100 - T] =0.16 * 100
0.1T + 20 - 0.2T = 16
- 0.1T =16 - 20 = - 4
T = - 4 / - 0.1
T = 40 grams of 10% titanium
100 - 40 = 60 grams of 20% titanium
Check: [40 grams x 0.1] + [60 grams x 0.2] =0.16 x 100 grams = 16 = 16

 Aug 20, 2020

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