a metallurgist has an alloy with 10% titanium and an alloy with 20% titanium. he needs 100 grams of an alloy with 16% titanium. how much of each alloy should be mixed to attain the 100 grams of alloy with 16% titanium?

Guest Aug 20, 2020

#1**0 **

Let the number of grams of 10%titanium needed=T

Then, the number of grams of 20% titanium needed =100 - T

0.1T + 0.2[100 - T] =0.16 * 100

0.1T + 20 - 0.2T = 16

- 0.1T =16 - 20 = - 4

T = - 4 / - 0.1

T = **40 grams of 10% titanium**

100 - 40 = **60 grams of 20% titanium**

Check: [40 grams x 0.1] + [60 grams x 0.2] =0.16 x 100 grams = 16 = 16

Guest Aug 20, 2020