+0

0
274
2
+103

at 9:00(o'clock) a truck left from  city A heading to city B, at 10:00(o'clock) a taxi left from city B heading to city A. the constent speed of the truck was 25% less than the taxi's constent speed. the truck and the taxi drove the through the same road and met at 12:00 ( o'clock). what is the trucks constent speed if the distance from city A to city B is 360km ?

(side note : i am translating this from Hebrew so i am sorry for any misspells or errors i have made and thank you for trying to solve this and helping me)

BlindxD  Aug 23, 2014

#1
+26412
+10

Let taxi speed be v km per hour, so truck speed is 0.75v kph.

Truck travels for 3 hours, so distance travelled by truck in that time = 0.75v*3 = 9v/4 km

Taxi travels for 2 hours, so distance travelled by taxi in that time = 2v km

These must total 360 km so:   2v + 9v/4 = 360 or 17v/4 = 360

v = 4*360/17 = 84.71 kph

So truck speed = 0.75*4*360/17 = 63.53 kph

Alan  Aug 23, 2014
Sort:

#1
+26412
+10

Let taxi speed be v km per hour, so truck speed is 0.75v kph.

Truck travels for 3 hours, so distance travelled by truck in that time = 0.75v*3 = 9v/4 km

Taxi travels for 2 hours, so distance travelled by taxi in that time = 2v km

These must total 360 km so:   2v + 9v/4 = 360 or 17v/4 = 360

v = 4*360/17 = 84.71 kph

So truck speed = 0.75*4*360/17 = 63.53 kph

Alan  Aug 23, 2014
#2
+103
0

thank you for your help Alan but at the end i solved it with the S│V│T method and again, thank you so much for helping me ☺☻☺☻☺☻

BlindxD  Aug 23, 2014

### 19 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details