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Let  G be the center of equilateral triangle XYZ.  A dilation centered at G with scale factor -4/3 is applied to triangle XYZ, to obtain triangle X'Y'Z'. Let A be the area of the region that is contained in both triangles XYZ and X'Y'Z' .  Find A/xyz?

 Apr 16, 2021
 #1
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please hel cphill 

also cphill did you create this website

 Apr 16, 2021
 #2
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The answer is 25/27.

 Apr 16, 2021
 #3
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Thx for the attempt guest but that isn't right does anyone else have an aswer please

Guest Apr 16, 2021
 #4
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What is      A/xyz      I do not understand what I am being asked to find ???

 

The ratio of the areas is 9:16  but I really do not know if that is what you want......

 Apr 16, 2021
 #5
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Thank You for the help melody but that isn't right and what they mean for A/XYZ is like the total area over XYZ' area. Thank you for he attempt.

Guest Apr 16, 2021
 #8
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What I have done is correct.  It is what is being asked for that is the problem.  

Melody  Apr 18, 2021
 #6
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pls help the answers that were attempted were not write and please have explanation thx

 Apr 17, 2021
 #7
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I have already told you, the ratio of the areas is 9:16

 

From this you can work out the ratio that you are being asked for.

What is being asked for is still not written clearly,  but you seem to understand what your teacher wants.

 

 

Hint the total area is  9+16, little,original area = 9   big dilated area =16

 Apr 18, 2021

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