ahhh the formatting is scary but here we go! \( $\sqrt[3]{\frac{8}{\sqrt{27}}}\) \(\frac{a\sqrt{b}}{c}, a+b+c?\)
Ok so first you need to simpify the first expression which is 2/3 because
cube root of 8= 2
so next you would need to say that radical 27 is basically 27 to the power of 1/2 and put it under the cube root and simplify
and you would get \(2\sqrt{3}/3 \) and then you need to add the 3 numbers so it would be 8.
(´・ω・`) (´・ω・`) (´・ω・`)