Monica is trying to solve the following equation by completing the square: \(x^2-8x+8 = 0\)She successfully rewrites the above equation in the following form: \((x + b)^2 = c\),where b and c are integers. What is the value of b+c?
x2 - 8x + 8 = 0
Subtract 8 from both sides.
x2 - 8x = -8
Add (-8/2)2 = 16 to both sides.
x2 - 8x + 16 = -8 + 16
Factor left side and simplify right side.
(x - 4)2 = 8
(x + b)2 = c
You can see that
b = -4 and c = 8
So.. -4 + 8 = 4
thanks
+4609 
