+0

+1
273
2
+1916

Monica is trying to solve the following equation by completing the square: \(x^2-8x+8 = 0\)She successfully rewrites the above equation in the following form: \((x + b)^2 = c\),where b and c are integers. What is the value of b+c?

tertre  Apr 6, 2017

#1
+6616
+4

x2 - 8x + 8 = 0

Subtract 8 from both sides.

x2 - 8x = -8

Add (-8/2)2 = 16 to both sides.

x2 - 8x + 16 = -8 + 16

Factor left side and simplify right side.

(x - 4)2 = 8

(x + b)2 = c

You can see that

b = -4 and c = 8

So.. -4 + 8 = 4

hectictar  Apr 6, 2017
Sort:

#1
+6616
+4

x2 - 8x + 8 = 0

Subtract 8 from both sides.

x2 - 8x = -8

Add (-8/2)2 = 16 to both sides.

x2 - 8x + 16 = -8 + 16

Factor left side and simplify right side.

(x - 4)2 = 8

(x + b)2 = c

You can see that

b = -4 and c = 8

So.. -4 + 8 = 4

hectictar  Apr 6, 2017
#2
+1916
0

thanks

tertre  Apr 6, 2017

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