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avatar+2765 

Monica is trying to solve the following equation by completing the square: \(x^2-8x+8 = 0\)She successfully rewrites the above equation in the following form: \((x + b)^2 = c\),where b and c are integers. What is the value of b+c?

tertre  Apr 6, 2017

Best Answer 

 #1
avatar+7155 
+4

x2 - 8x + 8 = 0

 

Subtract 8 from both sides.

x2 - 8x = -8

 

Add (-8/2)2 = 16 to both sides.

x2 - 8x + 16 = -8 + 16

 

Factor left side and simplify right side.

(x - 4)2 = 8

(x + b)2 = c

 

You can see that

b = -4 and c = 8

 

So.. -4 + 8 = 4

hectictar  Apr 6, 2017
 #1
avatar+7155 
+4
Best Answer

x2 - 8x + 8 = 0

 

Subtract 8 from both sides.

x2 - 8x = -8

 

Add (-8/2)2 = 16 to both sides.

x2 - 8x + 16 = -8 + 16

 

Factor left side and simplify right side.

(x - 4)2 = 8

(x + b)2 = c

 

You can see that

b = -4 and c = 8

 

So.. -4 + 8 = 4

hectictar  Apr 6, 2017
 #2
avatar+2765 
0

thanks

tertre  Apr 6, 2017

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