A scientist has two acid solutions: Artesia, which is a 70% acid solution, and Borromeo, which is a 20% acid solution.
(a) Find the amount of Artesia (in mL) that must be added to 500 mL of Borromeo order to produce a 60% acid solution.
(b) Find the amount of Artesia and Borromeo (in mL) that can be combined in order to form a 100 mL solution that is $55\%$ acid.
(c) Does there exist a combination of Artesia and Borromeo that is 80% acid?
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a ) Let the volume required be v .
v x .7 + 500 x .2 / ( v + 500 ) = .7
.2 v + 250 = .6 v + 180
.1 v = 200
v = 2000 mL
Let the volume of solution Artesia required be v . The volume of solution of Borromeo required will be 100 - v
v x .7 + ( 100 - v ) x .2 / 100 = .55
.6 v + 20 - .7 v = 55
.5 v = 20
v = 40 mL
volume of solution Borromeo = 60 mL .
It is not possible because 90 % is more than 70 % the concentration of solution Artesia . Any mixture will have concentration less than 70 % .