A cowboy agreed to work for one year for 19,200 plus a horse. He quit after 7 months and was paid 10,450 plus a horse. How many dollars was the horse worth, if the paid salary reflects the fair proportion of his yearly salary?
Monthly pay = 19,200/12 = 1,600
Fair amount of his yearly salary = 1,600*7 = 11,200
And he was payed 10,450, so 11,200-10,450 = 750...
But apparently 750 is wrong, and I'm really confused. Did I do something wrong here?
Let the worth of the horse =H
[19200 + H] / 12 * 7 =10450 + H, solve for H
H =1,800 dollars - horse's worth.
Note: You could also set up a system of equations as follows:
[19200 + H] =12M [M =Months]..........(1)
[10450 + H] =7M...................................(2), solve for H, M
H = 1,800 dollars - Horse's worth.
M =1,750 - his gross monthly compensation[19200/12 + 1800/12 =1,750]
For 12 months he gets 19200 + a horse
that is 19200 / 12 = 1600 month
For SEVEN months he shoud have gotten 7 x 1600 + 7/12 horse = 11200 + 7/12 horse
he was shorted 11200 - 10450 = 750 and given 5/12 of a horse
so 5/12 of a horse is worth 750
then a WHOLE horse = 750 * 12/5 = $ 1800
