A cowboy agreed to work for one year for 19,200 plus a horse. He quit after 7 months and was paid 10,450 plus a horse. How many dollars was the horse worth, if the paid salary reflects the fair proportion of his yearly salary?

Monthly pay = 19,200/12 = 1,600

Fair amount of his yearly salary = 1,600*7 = 11,200

And he was payed 10,450, so 11,200-10,450 = 750...

But apparently 750 is wrong, and I'm really confused. Did I do something wrong here?

Guest Dec 22, 2020

#1**+1 **

Let the worth of the horse =H

[19200 + H] / 12 * 7 =10450 + H, solve for H

**H =1,800 dollars - horse's worth.**

Note: You could also set up a system of equations as follows:

[19200 + H] =12M [M =Months]..........(1)

[10450 + H] =7M...................................(2), solve for H, M

**H = 1,800 dollars - Horse's worth.**

M =1,750 - his gross monthly compensation[19200/12 + 1800/12 =1,750]

Guest Dec 22, 2020

edited by
Guest
Dec 22, 2020

#2**+1 **

For 12 months he gets 19200 + a horse

that is 19200 / 12 = 1600 month

For SEVEN months he shoud have gotten 7 x 1600 + 7/12 horse = 11200 + 7/12 horse

he was shorted 11200 - 10450 = 750 and given 5/12 of a horse

so 5/12 of a horse is worth 750

then a WHOLE horse = 750 * 12/5 = $ 1800

Guest Dec 22, 2020