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Find the product of all real values of $$r$$ for which $$\frac{1}{2x}=\frac{r-x}{7}$$ has exactly one real solution.

Jul 14, 2020

#1
+2311
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Let's make these have an equal denominator first...

$$7/14x = 2x(r-x)/14x$$

That will get us $$0=2x(r-x)/14x - 7/14x=0$$

Can you get it from here, or do you need more help?

Jul 14, 2020