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Find the product of all real values of \(r\) for which \(\frac{1}{2x}=\frac{r-x}{7} \) has exactly one real solution.

 Jul 14, 2020
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Let's make these have an equal denominator first...

 

\(7/14x = 2x(r-x)/14x\)

That will get us \(0=2x(r-x)/14x - 7/14x=0\)

 

Can you get it from here, or do you need more help?

 Jul 14, 2020

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