+0  
 
0
42
8
avatar

What is the sum of the coefficients of the expansion of (5a/3-2b/3)^10?

 Jul 14, 2023
 #1
avatar
-3

The sum of the coefficients of the expansion of (5a/3-2b/3)^10 is 1024.

The binomial theorem tells us that the sum of the coefficients of the expansion of (x+y)^n is given by 2^n. In this case, x = 5a/3 and y = -2b/3, so the sum of the coefficients is 2^10 = 1024.

Here is a proof of the binomial theorem:

(x+y)^n = nC0x^n + nC1x^(n-1)y + nC2x^(n-2)y^2 + ... + nCy^(n-1)x + y^n

The sum of the coefficients is given by

nC0 + nC1 + nC2 + ... + nCy^(n-1) + y^n

We can use Pascal's identity to simplify this expression:

nC0 + nC1 + nC2 + ... + nCy^(n-1) + y^n = (nC0 + y^n) + (nC1 + y^(n-1)) + ... + (nCn-1)

Pascal's identity tells us that nC0 + y^n = 2^n, so the sum of the coefficients is

2^n + (nC1 + y^(n-1)) + ... + (nCn-1)

This expression is always equal to 2^n. Therefore, the sum of the coefficients of the expansion of (x+y)^n is always 2^n.

In the case of (5a/3-2b/3)^10, x = 5a/3 and y = -2b/3, so the sum of the coefficients is 2^10 = 1024.

 Jul 14, 2023
 #2
avatar
+4

This is an example of a chat-gpt answer. Does it sound like chatGPT? Yes. Does ZeroGPT think it is? Yes. Is it correct? No. Is moderation going to do anything? No. "B-but we don't have any pwoof!!" I don't care. It's incorrect anyhow, and should be deleted. Of course, we are keen on protecting the egos of anonymous users more than the quality of the site.

Guest Jul 14, 2023
 #3
avatar
0

you are 100% right

Guest Jul 14, 2023
 #5
avatar
0

(5a/3  -  2b/3)^10?

 

(5/3  -  2/3) =1 - sum of the coefficients

 Jul 15, 2023
 #6
avatar
+2

Please don't give the correct answer.

Guest Jul 15, 2023
 #8
avatar+184 
0

ChatGPT's math skills are literally nonexistent. When I asked it a math question to see if everyone was right about it being terrible at math... it didn't even generate the possibility that x^3 = -8 and said it was impossible. But obviously -2^3 = -8. So DON'T use ChatGPT generated answers, they are useless. 

 Jul 19, 2023

1 Online Users