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Ted Krischak has a 0.78 chance of making par on each hole of golf that he plays. Today he plans to play just three holes. Find the binomial probability of each event. Round answers to three decimal places.

 

He makes par on all three holes

 

He makes par on exactly two of the three holes

 Apr 16, 2018
 #1
avatar+100513 
+2

Pars all three holes  =  (.78)^3  = .475  

 

Pars on any  2  of the holes  = C(3,2)(.78)^2 (.22)^1   = .402

 

 

cool cool cool

 Apr 16, 2018
 #2
avatar+1354 
+9

Hmm interesting question?

 Apr 16, 2018

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