Ted Krischak has a 0.78 chance of making par on each hole of golf that he plays. Today he plans to play just three holes. Find the binomial probability of each event. Round answers to three decimal places.


He makes par on all three holes


He makes par on exactly two of the three holes

Mekka86  Apr 16, 2018

Pars all three holes  =  (.78)^3  = .475  


Pars on any  2  of the holes  = C(3,2)(.78)^2 (.22)^1   = .402



cool cool cool

CPhill  Apr 16, 2018

Hmm interesting question?

IAmJeff  Apr 16, 2018

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