I don't understand what I am doing wrong for this question "In how many ways can a President, Vice-President, and Treasurer be chosen from a group of 4 guys and 4 girls and at least one girl and at least one guy holds at least one of those three positions? One person cannot serve in more than one position."
I tried doing 4*4*6 (for 4 boys and 4 girls then 6 for the remaining people). Could I get some help? Thanks :)
My GUESS (often wrong with these Q's)
4 c 1 for a girl in one of the offices = 4 ways
times 4c1 for a boy = 16 ways
can be bgx bxg xbg gbx gxb xgb 6 x 16 = 96
one office left choose from 6 remaining 96 x 6 = 576 ways (?????)
Let me know if I am incorrect...... and what the REAL answer is ! THANX ! ~EP
Hi EP! I tried doing this problem, and I got a different answer from you...but nice job! (you might actually be the right one!)
Here is how I did it:
Since there are a total of 8 people, we start out by multiplying by 8.
Next, whether the person is a boy or a girl, we need to choose someone from the other gender. That gives us 4.
Now, we multiply by what is remaining, which is 6.
8*4*6 = 192
I'm not to good with these questions either (my brain just keeps on thinking about "what ifs"), so my answer might not be correct.