1. The radius of the circle is the discance between P and Q. Plug these into the distance formula:
\(radius=\sqrt{(-3-9)^2+(4--3)^2}\)
\(radius=\sqrt{(-12)^2+(7)^2}\)
\(radius=\sqrt{193}\)
The formula for the area of a circle is \(\pi r^2\). Plug the radius into this to find the area.
\(\pi(\sqrt{193})^2\)
Area=\(\boxed{193\pi}\)
2. Find the largest value of n such that 3x^2+nx+72 can be factored as the product of two linear factors with integer coefficients.
We need the max sum of two factors that multiply to 72 and the same for two factors that multiply to 3
These are 1,72 and 1, 3
So......n will be maximized when we have
(3x + 1) (1x + 72) = 3x^2 + 1x + 216x + 72 = 3x^2 + 217x + 72
n = 217
\(\frac{2}{\sqrt[3]{4}+\sqrt[3]{32}} \) \(\frac{\sqrt[3]{A}}{B}\)
Multiply the top/bottom by ( 3√[4^2] - 3√[4*32] + 3√[32]^2 )
2 ( 3√[4^2] - 3√[4*32] + 3√[32]^2 )
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(3√4 + 3√32) ( 3√[4^2] - 3√[4*32] + 3√[32]^2 )
This resolves the demoninator into 4 + 32 = 36
So we have
2 ( 23√2 - 43√2 + 83√2 ) 63√2 3√2
_______________________ = ______ = _____
36 18 3
A = 2 B = 3
And their sum is 5