Bekah has exactly three brass house number digits: 2, 3 and 5. How many distinct numbers can she form using one or more of the digits?
Using one digit: 2, 3, 5
Using 2 digits: 23, 25, 32, 35, 52, 53
Using 3 digits: 235, 253, 325, 352, 523, 532
In total, she can form 15 numbers.
We can calculate it by considering permutations, which is \(P^3_1 + P^3_2 + P^3_3 = 3 + 6 + 6 = 15\)
thanks
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