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Bekah has exactly three brass house number digits: 2, 3 and 5. How many distinct numbers can she form using one or more of the digits?

 Jun 13, 2020
 #1
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+3

Using one digit: 2, 3, 5

Using 2 digits: 23, 25, 32, 35, 52, 53

Using 3 digits: 235, 253, 325, 352, 523, 532
 

In total, she can form 15 numbers.

 

We can calculate it by considering permutations, which is \(P^3_1 + P^3_2 + P^3_3 = 3 + 6 + 6 = 15\)

 Jun 13, 2020
 #2
avatar+338 
+3

thankssmiley

 Jun 13, 2020

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