+118687 I am reasonably sure I answered this one recently so why not just google it ?
+379 i tried, got no result (also tried through the webcalc search)
+118687 Well how many ways can it be done if you ignore the reflection bit ?
just fix one in place first and see how many permutations there are for the rest.
I am not so sure about the reflection bit BUT if the first one is fixed in place then how many axes of symmetry are there?
+379 thank you for the help, but i got 60 for the answer.
working out if anyone needs it
for a row, there would be 6! arrangements.
however, we divide this by 6 because some arrangements can be rotataed to form each other.
we also divide this by 2 because of reflectional symmetry.
6!/(6*2)=720/12=60
+118687 In how many ways can 6 distinct beads be placed on a bracelet? (Note that two arrangements are the same if one can be rotated or reflected to produce the other.)
Just put one of the beads down. (that takes care of rotation)
there are 5 beads left
there are 5! places to put them 5! = 120
Now given that the first place is fixed I think there is only one axis of symmetry that counts
120/2 = 60
We got the same answer but i won't guarentee that it is correct.
