+0

0
112
8
+397

deleted.

Nov 13, 2019
edited by sinclairdragon428  Nov 20, 2019

#1
+106993
0

I am reasonably sure I answered this one recently so why not just google it ?

Nov 13, 2019
#2
+397
-1

i tried, got no result (also tried through the webcalc search)

sinclairdragon428  Nov 13, 2019
#3
+106993
+1

Well how many ways can it be done if you ignore the reflection bit ?

just fix one in place first and see how many permutations there are for the rest.

I am not so sure about the reflection bit BUT if the first one is fixed in place then how many axes of symmetry are there?

Nov 13, 2019
#6
+397
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thanks melody!

sinclairdragon428  Nov 14, 2019
#4
0

There are 6*9 = 45 ways of arranging the beads.

Nov 13, 2019
#5
+397
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thank you for the help, but i got 60 for the answer.

working out if anyone needs it

for a row, there would be 6! arrangements.

however, we divide this by 6 because some arrangements can be rotataed to form each other.

we also divide this by 2 because of reflectional symmetry.

6!/(6*2)=720/12=60

sinclairdragon428  Nov 14, 2019
#7
+106993
+1

In how many ways can 6 distinct beads be placed on a bracelet? (Note that two arrangements are the same if one can be rotated or reflected to produce the other.)

Just put one of the beads down. (that takes care of rotation)

there are 5! places to put them   5! = 120

Now given that the first place is fixed I think there is only one axis of symmetry that counts

120/2 = 60

We got the same answer but i won't guarentee that it is correct.

Nov 14, 2019
#8
+397
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i checked and it was correct! thanks for your help melody

sinclairdragon428  Nov 14, 2019