What is the energy of a photon of light that has a frequency of 2.09 x 1016 Hz? You might need to know that c = 3 x 108 m/s and h = 6.63 x 10-34 Js. After you get your answer, take the LOG of it and enter that to 2 decimal places.
Why don't you use the well-known formula for the energy of elementary particles: E=hc/y. Since you don't have "y", which is the wavelength of the photon, then just multiply Planck's constant by "c", which is the speed of light. That should give you the energy of the photon in "Ev", or electron volts. It's going to be a very small number because of Planck's constant. However, you may have to calculate the wavelength of the photon by using the formula: y=c/f, "f" being the frequency of the photon.
Why don't try these and let us know what you got. Good luck.
