+816 The inverse of \(f(x) = \frac{2x-1}{x+5}\) may be written in the form \(f^{-1}(x)=\frac{ax+b}{cx+d}\), where \(a\), \(b\) , \(c\), and \(d\) are real numbers. Find \(a/c\).
+36915 y = 2x-1/x+5 First, solve for 'x'
yx+5y -2x = -1
yx - 2x= -5y -1
x(y-2) = -5y-1
x = (-5y-1)/(y-2) then switch the x's and y's to have the inverse f^-1 (x)
y = (-5x-1)/(x-2) a = -5 c= 1 a/c -5/1 = -5
+36915 y = 2x-1/x+5 First, solve for 'x'
yx+5y -2x = -1
yx - 2x= -5y -1
x(y-2) = -5y-1
x = (-5y-1)/(y-2) then switch the x's and y's to have the inverse f^-1 (x)
y = (-5x-1)/(x-2) a = -5 c= 1 a/c -5/1 = -5
