\(A=32x^2+8x = \ell \cdot w\\ A = 8x(4x+1)\\ \text{Given the info you've provided there's really no further we can go}\\ \ell = 8x \\ w = (4x+1)\ \text{all you can really say about }x \text{ is }\\ x>0 \text{ since length must be positive}\)
\(A=32x^2+8x = \ell \cdot w\\ A = 8x(4x+1)\\ \text{Given the info you've provided there's really no further we can go}\\ \ell = 8x \\ w = (4x+1)\ \text{all you can really say about }x \text{ is }\\ x>0 \text{ since length must be positive}\)