Processing math: 100%
 
+0  
 
0
643
1
avatar

hey, guys, I

need help ASAP I can't figure this out...

 

 

find the dimensions for a rectangle with the area of...

A=32x^2 + 8x

 

help me, please

 Dec 19, 2018

Best Answer 

 #1
avatar+6251 
+2

A=32x2+8x=wA=8x(4x+1)Given the info you've provided there's really no further we can go=8xw=(4x+1) all you can really say about x is x>0 since length must be positive

.
 Dec 19, 2018
 #1
avatar+6251 
+2
Best Answer

A=32x2+8x=wA=8x(4x+1)Given the info you've provided there's really no further we can go=8xw=(4x+1) all you can really say about x is x>0 since length must be positive

Rom Dec 19, 2018

4 Online Users

avatar
avatar
avatar