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Solve for : x

\( x^2 + 4x + 3 = -(x + 3)(x + 5). \)

Thanks help when you can :)

Aug 13, 2020

#1
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Factor L side to   (x+3)(x+1)          then cancel   (x+3) from both sides of the equation and solve....   x+1 = - (x+5)

Aug 13, 2020
#2
+130
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this is incorrect thanks for trying though

Aug 13, 2020
#4
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Not sure why you say it is incorrect,

if you solve as instructed:       x+1 = - (x+5)       you will find   x = -3

I think YOU are incorrect...  thanx for not really  trying though !

Guest Aug 13, 2020
#5
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You can only cancel x+3 from borh sides (i.e. divide both sides by x+3) as long as x+3 is not zero.  Here, x+3 turns out to be zero.

Fortuitously, you still get the right answer in this case!  However, performing mathematically illegal operations is not valid, whatever the apparent result.

Alan  Aug 13, 2020
#6
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I am so sorry i didnt read it right omg i am really sorry

Creampuff  Aug 13, 2020
#3
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Solve for x:
x^2 + 4 x + 3 = -(x + 3) (x + 5)

Expand out terms of the right hand side:
x^2 + 4 x + 3 = -x^2 - 8 x - 15

Add x^2 + 8 x + 15 to both sides:
2 x^2 + 12 x + 18 = 0

Divide both sides by 2:
x^2 + 6 x + 9 = 0

Write the left hand side as a square:
(x + 3)^2 = 0

Take the square root of both sides:
x + 3 = 0

Subtract 3 from both sides:

x = -3

Aug 13, 2020