Help please!

It says 10√6 is incorrect, do you know where you went wrong?

$y\ =\ \frac{15\sqrt{24}}{\sqrt{x}}$

What is  x  when  y = 3 ?  Plug in  3  for  y  and solve for  x .

$3\ =\ \frac{15\sqrt{24}}{\sqrt{x}}$

To solve for  x ,

divide both sides of the equation by  15

then square both sides of the equation

then multiply both sides of the equation by  x

then multiply both sides of the equation by  $\frac{225}{9}$

Can you do those things sinclairdragon?  If you get stuck let us know!

I got to 1/25x = \sqrt24 but i'm not sure where to go from there.

$3\ =\ \frac{15\sqrt{24}}{\sqrt{x}}$

                        Divide both sides of the equation by  15

$\frac{3}{15}\ =\ \frac{\sqrt{24}}{\sqrt x}$

                                        Square both sides of the equation.

$\Big(\frac{3}{15}\Big)^2\ =\ \Big(\frac{\sqrt{24}}{\sqrt x}\Big)^2$

                                        Simplify both sides using the rule  $\big(\frac{a}{b}\big)^2\ =\ \big(\frac{a}{b}\big)\big(\frac{a}{b}\big)\ =\ \frac{a^2}{b^2}$

.$\frac{3^2}{15^2}\ =\ \frac{(\sqrt{24}\,)^2}{(\sqrt x\,)^2}$

$\frac{9}{225}\ =\ \frac{24}{x}$

                              Now multiply both sides of the equation by  x

$x\cdot\frac{9}{225}\ =\ 24$

                                                  Multiply both sides of the equation by  $\frac{225}{9}$

$x\cdot\frac{9}{225}\cdot\frac{225}{9}\ =\ 24\cdot\frac{225}{9}$

$x\ =\ 24\cdot\frac{225}{9}$

$x\ =\ 600$

Thanks!