Help Please

Thanks, guest......here's the way to do this with a substitution

-4x-15y=-17 and -x+5y=-13

Rearranging the second equation, we have    x = 5y + 13

Substitute this into the first equation  for y

-4[5 y + 13] - 15y  = -17    simplify

-20y - 52 - 15y  = -17

-35y  =  35     divide both sides by -35

y = -1 

And using   x = 5y + 13

x = 5(-1) + 13    =   8

Solve the following system:
{-4 x-15 y = -17 |     (equation 1)
5 y-x = -13 |     (equation 2)
Subtract 1/4 × (equation 1) from equation 2:
{-(4 x)-15 y = -17 |     (equation 1)
0 x+(35 y)/4 = (-35)/4 |     (equation 2)
Multiply equation 1 by -1:
{4 x+15 y = 17 |     (equation 1)
0 x+(35 y)/4 = -35/4 |     (equation 2)
Multiply equation 2 by 4/35:
{4 x+15 y = 17 |     (equation 1)
0 x+y = -1 |     (equation 2)
Subtract 15 × (equation 2) from equation 1:
{4 x+0 y = 32 |     (equation 1)
0 x+y = -1 |     (equation 2)
Divide equation 1 by 4:
{x+0 y = 8 |     (equation 1)
0 x+y = -1 |     (equation 2)
Collect results:
Answer: | x = 8                   and                y = -1