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Let $ABCD$ be a trapezoid with bases $\overline{AB}$ and $\overline{CD}.$ Let $AD=5$ and $BC=7,$ and let $P$ be a point on side $\overline{CD}$ such that $\frac{CP}{PD}=\frac{7}{5}.$ Let $X,Y$ be the feet of the altitudes from $P$ to $\overline{AD},$ $\overline{BC}$ respectively. Show that $PX=PY.$

Nov 17, 2019

#1
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Please do not discuss this problem!  This is an active homework problem.

To the original poster: I realize that homework may be challenging. If you wish to receive some help from the staff or other students, I encourage you to use the resources that the online classes provide, such as the Message Board.  Thanks.

Nov 17, 2019
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so lazy he didn't even remove latex or converted

Nov 17, 2019
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Wait i do aops and this was one of our homework problems!!!!!

nyxLeauge  Nov 21, 2019