This is the complicated answer given by Wolfram/Alpha:
{x element R : 6 x + sqrt(37)<1 or (6 x + sqrt(13)>1 and 6 x<1 + sqrt(13)) or 6 x>1 + sqrt(37) or 1/6 (1 - sqrt(37))<x<-2/3 or -2/3<x<1/6 (1 - sqrt(13)) or 1/6 (1 + sqrt(13))<x<1 or 1<x<1/6 (1 + sqrt(37))}
(assuming a function from reals to reals). See the link here:
http://www.wolframalpha.com/input/?i=Domain++y%3D+1+%2F+Log(abs%5B3x%5E2+-+x+-+2%5D)&rawformassumption=%7B%22C%22,+%22Domain%22%7D+-%3E+%7B%22DomainAndRangeWord%22%7D&rawformassumption=%7B%22FunClash%22,+%22Log%22%7D+-%3E+%7B%22Log10%22%7D
The absolute value bars mean that this is only undefined when :
3x^2 - x - 2 = 0 factor
(3x + 2) (x - 1) = 0 set each factor to 0 and x = -2/3 or x = 1
Thus....all x values are in the domain except x = -2/3 and x = 1
Here's the graph : https://www.desmos.com/calculator/uuzamhwcht