Find the ordered pair that satisfies the system of equations
\(\begin{align*} x+3y &= -4,\\ 3x -7y &= 36. \end{align*}\)
+238 Multiply first equation by 3,
\(3x + 9y = -12\)
\(3x -7y = 36\)
Subtract,
\(16y = -48\)
\(y = -3\)
Plug y back into one of the equations,
\(x -9 = -4 \)
\(x = 5\)
So (x, y) = (5, -3)
+874 $-9x - 27y = 36$
$3x - 7y = 36$
$3x - 7y = -9x - 27y$
$12x = -20y$
$3x = -5y$
$x = - \frac{5}{3} y$
$3x + 9y = -12$
$16y = -48$
$y = -3$
$x = 5$
$(x,y) = (5, -3)$
