Find all real solutions for x in \( 2(2^x- 1) x^2 + (2^{x^2}-2)x = 2^{x+1} -2 . \)
Thanks for your time!
The solutions are x = -2, x = 2, and x = 5.
Could you please explain to me how you got those answers?
Can you confirm whether you intend
\({2^{x^{2}}}={2^{(x^{2})}}\quad or \quad {(2^{x}})^{2}\)
I think if your notation is correct it should be the first one.
That is the one I have been playing with. But so far I am baffled.
Yeah, I mean the former.
Assuming \(2^{x^2} \) means \(2^{(x^2)}\) then:
Thanks!
+101 
