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Find all real solutions for x in \( 2(2^x- 1) x^2 + (2^{x^2}-2)x = 2^{x+1} -2 . \)

 

 

Thanks for your time!

 Feb 24, 2020
 #1
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-1

The solutions are x = -2, x = 2, and x = 5.

 Feb 25, 2020
 #2
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Could you please explain to me how you got those answers?

 Feb 26, 2020
 #3
avatar+110100 
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Can you confirm whether you intend

 

\({2^{x^{2}}}={2^{(x^{2})}}\quad or \quad {(2^{x}})^{2}\)

 

I think if your notation is correct it should be the first one. 

That is the one I have been playing with.  But so far I am baffled.

 Feb 29, 2020
 #5
avatar+102 
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Yeah, I mean the former. 

chclt363  Mar 2, 2020
 #4
avatar+30595 
+6

Assuming \(2^{x^2} \) means \(2^{(x^2)}\) then:

 

 Feb 29, 2020
 #6
avatar+102 
0

Thanks!

chclt363  Mar 2, 2020

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