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0
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Find all real solutions for x in $$2(2^x- 1) x^2 + (2^{x^2}-2)x = 2^{x+1} -2 .$$

Feb 24, 2020

#1
-1

The solutions are x = -2, x = 2, and x = 5.

Feb 25, 2020
#2
+86
0

Feb 26, 2020
#3
+108725
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Can you confirm whether you intend

$${2^{x^{2}}}={2^{(x^{2})}}\quad or \quad {(2^{x}})^{2}$$

I think if your notation is correct it should be the first one.

That is the one I have been playing with.  But so far I am baffled.

Feb 29, 2020
#5
+86
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Yeah, I mean the former.

chclt363  Mar 2, 2020
#4
+29252
+5

Assuming $$2^{x^2}$$ means $$2^{(x^2)}$$ then:

Feb 29, 2020
#6
+86
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Thanks!

chclt363  Mar 2, 2020