If sin(x) = 8/17 and x is an acute angle, find cot(x). Please draw a reference triangle

Thank you!

nicoledakota2290 Feb 25, 2021

#1**+1 **

Acute angle so sin and cos are positive and so is cot = cos/sin

sin^2 + cos^2 = 1

cos ^2 = 1- (8/17)^{2} = 225 / 289

cos = 15/17

cot = cos / sin = .........

ElectricPavlov Feb 25, 2021

#2**+1 **

The question asked for a reference triangle.

Remember that sin is opposite over hypotenuse, meaning that the side opposite to angle with measure $x$ is $8$ and the hypotenuse is $17$. Use the Pythagorean theorem to find the other side. Then, use that $\cot(x)=\frac{\cos(x)}{\sin(x)}$, recalling that $\cos=\frac{\text{adjacent}}{\text{hypotenuse}}$.

(Remember: Soh Cah Toa!)

thedudemanguyperson Feb 25, 2021