Hey! I have a question for this problem:
In quadrilateral PQRS, sides PS and QR have equal length and sides PQ and RS are parallel to each other. Point X is the intersection of the diagonals PR and QS. Which of the following conclusions must be true?
A) triangle PXQ is congruent to triangle RXS
B) triangle SPR is congruent to triangle RQS
C) triangle SPQ is congruent to triangle QRS
I believe it's A and C, but I'm not sure. can someone confirm?
Draw a pic. of a random quadrilateral. One that does not look very special
Call it PQRS
Mark on it the things that are told to you.
Redraw it so that it looks more like it is supposed to. But do not give it extra special features that are no specified (unless it is unavoidable)
What shape is it?
Now test all those possibilities and you will see that only one seems right.
It's only C !!!
Your shapes are right.
The most general one is the Trapezoid (In Australia we would call it a trapezium)
But unfortunately, your conclusion is not correct. (unless I have made some really stupid error)
Draw your trapezoid and re-check your result