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Let line \(l_1\) be the graph of \(5x + 8y = -9 \) . Line  \(l_2\)is perpendicular to line  \(1_1\)and passes through the point \((10,10)\). If line \(1_2\) is the graph of the equation \(y = mx +b\) , then find \(m+b\).

 Oct 8, 2018
 #1
avatar+99702 
+1

L1   =  5x + 8y  = -9

In the form  Ax + By  = C....the slope of this line  is  -A / B

So...the slope of this line  =  -5/8

 

And the slope of a line perpendicular to this   =  8/5   = slope of L2

 

So....we have this equation of L2  that passes through (10, 10)

 

y  = (8/5)(x -10) + 10

 

y  = (8/5)x - 16 + 10

 

y  = (8/5)x  - 6

 

m  = 8/5     b  = -6      and their sum is   8/5 + (-6)  =  8/5 + (-30/5)  = -22/5

 

 

cool cool cool

 Oct 8, 2018
 #2
avatar+144 
+1

Thankyou!!

HelpPLZ  Oct 8, 2018

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