The height, h, in feet of a golf ball above the ground after being hit into the air is given by the equation, h = -16t 2 + 64t, where t is the number of seconds elapsed since the ball was hit. How many seconds does it take for the golf ball to hit the ground?
It will take ______________ a0 seconds for the ball to hit the ground.
When h = 0 the ball is on the ground.....solve for h=0
0 = -16T^2 + 64T
0= t(-16 t + 64) so t = 0 is one choice,,,,this would be before the ball is hit.
0 = -16t+64
16t = 64
t = 4 sec when the ball lands