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# Help please

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I need help with this question. Can someone explain with a step by step visual?

Let G be the center of equilateral triangle XYZ. A dilation centered at G with scale factor -3/4 is applied to triangle XYZ, to obtain triangle X'Y'Z' Let A be the area of the region that is contained in both triangles XYZ and X'Y'Z' Find A/XYZ.

If someone could help me with this that would be great!

May 1, 2022

### 4+0 Answers

#1
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A/[XYZ] = 9/16.

May 1, 2022
#2
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can you explain to me how you got that answer? Though I do appreciate the attempt!

Guest May 1, 2022
#3
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A dilation with scale factor k applies a scale factor of k^2 on the area, so A/[XYZ] = (-3/4)^2 = 9/16.

May 2, 2022
#4
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The area of the small one is certainly 9/16 of the big one but I do not think that this is what the question is asking ...

At least that is not how i interpreted it.

I interpreted it as the intersection of the  areas divided by the original big area.  This is a harder question.

May 2, 2022