I need help with this question. Can someone explain with a step by step visual?
Let G be the center of equilateral triangle XYZ. A dilation centered at G with scale factor -3/4 is applied to triangle XYZ, to obtain triangle X'Y'Z' Let A be the area of the region that is contained in both triangles XYZ and X'Y'Z' Find A/XYZ.
If someone could help me with this that would be great!
A/[XYZ] = 9/16.
A dilation with scale factor k applies a scale factor of k^2 on the area, so A/[XYZ] = (-3/4)^2 = 9/16.
The area of the small one is certainly 9/16 of the big one but I do not think that this is what the question is asking ...
At least that is not how i interpreted it.
I interpreted it as the intersection of the areas divided by the original big area. This is a harder question.