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 Jun 10, 2019
edited by sinclairdragon428  Nov 20, 2019
 #1
avatar+681 
+1

ok so first you need to find the line thats perpendicular to y=2x-2  and that is y=-1/2x+b 
next solve for the y intercept, and i got 3 so now the equation would be y=-1/2x+3 
now you need to find the point of intersection between the two points so you would use either subsitution or elimination or any other method you are comfortable with. 
I used substitution: 
2x-2=-0.5x+3
x=2 
y=2 
and then you would need to find the distance between the points (2,2) and (6.0) so you would use the distance formula:
\(\sqrt{(-2)^2+(4)^2}\)

\(\sqrt{4+16}\)

\(\sqrt{20 }\)

\(2\sqrt{5}\)
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 Jun 11, 2019
 #2
avatar+397 
0

Thanks!

sinclairdragon428  Jun 11, 2019
 #3
avatar+681 
+1

no problem, hope it helped!smiley

Nirvana  Jun 11, 2019

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