Alex has 67 quarters and dimes worth $13.45.how many coins of each does he have?
+291 13.35/0.25=53.8
you cant have .8 coins so he had 53 whole coins
53*0.25= 13.25
now just fill in the difference with the dimes
so
13.45-13.25=20
20/0.10=2
he has 53 quarters and 2 dimes
hope it helped
+209 Are you sure the problem you posted is correct? Dimes and quarters can't go into $13.45 if I'm correct.
Alex has 67 quarters and dimes worth $13.45.how many coins of each does he have?
Let the number of quarters=Q
Let the number of dimes =D
Q + D =67
.25Q + .10D=13.45, so that Alex has:
45 Quarters and
22 Dimes
Solve the following system: {D+Q = 67 | (equation 1) 0.1 D+0.25 Q = 13.45 | (equation 2) Subtract 0.1 × (equation 1) from equation 2: {D+Q = 67 | (equation 1) 0 D+0.15 Q = 6.75 | (equation 2) Divide equation 2 by 0.15: {D+Q = 67 | (equation 1) 0. D+Q = 45. | (equation 2) Subtract equation 2 from equation 1: {D+0 Q = 22. | (equation 1) 0 D+Q = 45. | (equation 2) Collect results: Answer: | | {D = 22. Q = 45.
