+140 A parrallelogram P Q R S all inter sect at T
PT=Y
TR=4X+1
QT=2Y
TS=3X+12
Solve for X and Y
+118667 The meaning of your question is not clear ://
I assume P Q R and S are all points. How can they intersect at another point. It makes no sense.
+33657 If we assume Kallamoar meant that the diagonals intersect at T, then using the fact that the diagonals of a parallelogram bisect each other we have:
Y = 4X + 1 (1)
2Y = 3X + 12 (2)
Subtract eqn(2) from 2*eqn(1): 0 = 5X - 10 so 5X = 10 or X = 2
Substitute this into eqn(1) to get Y = 4*2 + 1 or Y = 9
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