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If x = 4 (mod19) and y = 7 (mod19), then find the remainder when (x + 1)^2 (y + 5)^3 is divided by 19.

Apr 25, 2019
edited by er1004  Apr 25, 2019
edited by er1004  Apr 25, 2019

#2
+8341
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$$\begin{cases} x\equiv 4\pmod{19}\\ y\equiv 7\pmod{19}\\ \end{cases}\\ (x+1)^2 (y+5)^3\\ \equiv (4+1)^2 (7+5)^3 \pmod{19}\\ \equiv 43200 \pmod {19}\\ \equiv 13 \pmod{19}$$

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Apr 25, 2019
#3
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Many people have already mentioned this to you, but I will just remind you here again -

STOP USING THIS AS A CHEATING SITE

You have said many times previously that YOU ARE ONLY INTRESTED IN ANSWERS and not actually how to do them.

Please stop using this as a cheating site, it gets frustrating for everyone else

Apr 26, 2019