For a certain positive integer m, the equationhas 137 solutions in integers n. Find m.
This seems difficult.......!!!
Let's see if we can find a pattern.....
floor [sqrt (1) ] to floor [ sqrt (3)] have the same result = 1 ⇒ 3 occurences
floor [sqrt (4) ] to floor [ sqrt (8)] have the same result = 2 ⇒ 5 occurences
floor [ sqrt (9)] to floor [ sqrt (15)] have the same result = 3 ⇒ 7 occurences
floor [ sqrt (16) to floor [sqrt (24)] have the same result = 4 ⇒ 9 occurences
floor [sqrt (25)] to floor [sqrt (35)] have the same result = 5 ⇒ 11 occurences
So...it appears that 2(result) + 1 = the number of occurences
And we need 137 occurences
So we need to solve this:
2 (result) + 1 = 137 subtract 1 from both sides
2 (result) = 136 divide both sides by 2
result = 68
But we need to square this to find the first "n" = 68^2 = 4624
And the last "n" = 4624 + 136 = 4760
Check
floor [ sqrt (4623)] = 67
floor [ sqrt (6084)] = 68
floor [sqrt (4760)] = 68
floor [ sqrt (4761)] = 69
So m = 68