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avatar+385 

1.What is the y-coordinate of the y-intercept of the line that passes through the point (2,-3) and has slope 1/2
2. Rationalize the denominator: $$\frac{4}{\sqrt{108}+2\sqrt{12}+2\sqrt{27}}.$$

Thanks!

 Jun 11, 2019
 #1
avatar+8778 
+3

1.

 

equation of line that passes through  (2, -3)  with a slope of  \(\frac12\)  is

 

y + 3  =  \(\frac12\)(x - 2)

 

y + 3  =  \(\frac12\)x - 1

 

y  =  \(\frac12\)x - 4

 

The y-intercept is the point where  x = 0 . When  x = 0 ,

 

y  =  \(\frac12\)(0) - 4  =  -4

 

When  x  is  0 ,  y  is  4 .  So the y-coordinate of the y-intercept is  4 .

 Jun 11, 2019
 #3
avatar+385 
+1

It says the answer is incorrect, do you know where you went wrong?

sinclairdragon428  Jun 11, 2019
 #4
avatar+104704 
+2

Hectictar's answer is correct

 

She just made a typo....the y intercept  is  -4

 

cool cool cool

CPhill  Jun 11, 2019
 #5
avatar+385 
+1

Thank you!

sinclairdragon428  Jun 11, 2019
 #2
avatar+104704 
+2

           4    

__________________  =

√108 + 2√12 + 2√27

 

            4

___________________  =

 6√3 + 4√3 + 6√3

 

 

             4                                   √3                             4√3                √3

____________________ *      ______   =                _____   =       ____  

          16√3                                 √3                             48                 12

 

 

cool cool cool                 

 Jun 11, 2019

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