If I choose four cards from a standard 52-card deck, with replacement, what is the probability that I will end up with one card from each suit?
Since there is replacement, any card can be the first. Any card except the 13 of the first suit can be the secon. Any card except the 26 of the first & second suits. And theres only 13 cards left.
1*3/4*2/4*1/4=3/32
If I choose four cards from a standard 52-card deck, with replacement, what is the probability that I will end up with one card from each suit?
Since you replaced each card after it was chosen, you end up with no cards, because you put them all back. So, literally, the probability is zero. If this isn't a trick question, then a better wording of the question would have been "If I choose four cards from a standard 52-card deck, with replacement, what is the probability that I will end up with will have drawn one card from each suit?"
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