+0

-1
201
7

deleted.

Nov 15, 2019
edited by sinclairdragon428  Nov 20, 2019

#1
0

well in the 5 times, there are 30 faces

Each roll has atleast one "6" in it, you want to find the probability "If we get a 6 at most in 2 of the rolls only right?"

so in 2 times, there are two "6",

and in 2 rolls there are 6*2=12 possibility

2/12= 1/6

Nov 15, 2019
#2
+1

I did not get that.

This is a combination question.

You have to work out the prob of 0 + prob of 1 + prob of 2

That should get you started.

Melody  Nov 15, 2019
#3
+2

Each dice has a 1/6 chance to roll a six which means there are 6^5 possible rolls that 5 dice could have

if we isolate the roles that have a six, that means we are dividing the equation by 6

because only a 6th of them have a six, which brings it down to 6^4 possible roles

then we isolate the next six which would be the same thing because only a 6th of them have a six

so it would be 6^3 possible roles

next we need to turn 6^3 possible roles in to a fraction which involes divididing it from 6^5

which would be a 1/6^2 chance or 1/32 chance of roling a pair of sixes

I should mention the reason why I know this is because I was bored and wanted to know the

chances of getting a yatzee on the first roll (which is 1/6^4 by the way)

Nov 15, 2019
#4
+1

Thanks for having a go ChessPlayer   BUT     I don't think so . Melody  Nov 15, 2019
#5
0

Casewrok gives us 5^3 + 5^4 + 5^5 = 3875 possible rolls, so the answer is 3875/7776.

Nov 17, 2019
#6
0

Still no bananas.  This is a combination question.

Melody  Nov 17, 2019
#7
0

I am closing this as sinclairdragon is obviously not interested in discussing anything.

He is only interested in the final answer.

I know this becasue he has reposted.  I have locked that one too.

I do not want this site to be known primarily as a cheat site.

Nov 18, 2019
edited by Melody  Nov 18, 2019