well in the 5 times, there are 30 faces
Each roll has atleast one "6" in it, you want to find the probability "If we get a 6 at most in 2 of the rolls only right?"
so in 2 times, there are two "6",
and in 2 rolls there are 6*2=12 possibility
Each dice has a 1/6 chance to roll a six which means there are 6^5 possible rolls that 5 dice could have
if we isolate the roles that have a six, that means we are dividing the equation by 6
because only a 6th of them have a six, which brings it down to 6^4 possible roles
then we isolate the next six which would be the same thing because only a 6th of them have a six
so it would be 6^3 possible roles
next we need to turn 6^3 possible roles in to a fraction which involes divididing it from 6^5
which would be a 1/6^2 chance or 1/32 chance of roling a pair of sixes
I should mention the reason why I know this is because I was bored and wanted to know the
chances of getting a yatzee on the first roll (which is 1/6^4 by the way)
Casewrok gives us 5^3 + 5^4 + 5^5 = 3875 possible rolls, so the answer is 3875/7776.
I am closing this as sinclairdragon is obviously not interested in discussing anything.
He is only interested in the final answer.
I know this becasue he has reposted. I have locked that one too.
I do not want this site to be known primarily as a cheat site.