+0

+1
52
3
+604

What number can we place in the box to make the quadratic below the square of a binomial:

\( x^2 + \dfrac{5}{3}x + \boxed{\phantom{000}}. \)

gueesstt  Apr 22, 2018

#1
+646
+3

Hi gueesstt, to make this a square of a bunomial, we must take the square of one half of the coefficient of the term where the degree of x is 1.

So the coefficient of the term where the degree of x is 1, is 5/3.

We must take the square of one half of that.

First, one half of 5/3 is 5/6.

Then we take the square of that, which is 25/36.

That is the number that makes the quadratic a square of a binomial.

GYanggg  Apr 22, 2018
Sort:

#1
+646
+3

Hi gueesstt, to make this a square of a bunomial, we must take the square of one half of the coefficient of the term where the degree of x is 1.

So the coefficient of the term where the degree of x is 1, is 5/3.

We must take the square of one half of that.

First, one half of 5/3 is 5/6.

Then we take the square of that, which is 25/36.

That is the number that makes the quadratic a square of a binomial.

GYanggg  Apr 22, 2018
#3
+604
+1

Thank you so much!

gueesstt  Apr 22, 2018
#2
+646
+2

I'm done for today, I will continue on the rest of your problem tommorow.

I know how to do them but I'm just too tired.

GYanggg  Apr 22, 2018