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The points P = (x1, y1) and ! = (x2, y2) are the intersections of the parabola y^2 = 4ax, where a > 0, and a line passing through the focus of the parabola. Then the distance PQ can be expressed in the form c1x1 + c2x2 + c3a, where c1, c2, and c3 are constans. Compute c1 + c2 + c3.

 Jul 7, 2021
 #1
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$c_1 + c_2 + c_3 = 2$.

 Aug 14, 2021

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