(Track and Field) The position (h) of a high jumper with respect to time is given by the function h(t)=-3.11t^(2)+9.33t. If h is in feet and t is in seconds, find the jumper's vertical speed in feet per second (fps), at t=1 seconds. In other words, find (dh)/(dt), the change in position over the change in time, which is the rate, or vertical speed of the jumper. Round to 1 d.p.
Take the derivative of the function
h' t = -6.22t + 9.33
At 1 sec we have
h'(1) = -6.22 (1) + 9.33 ≈ 3.1 ft/s