+0

0
229
1

when a passenger jet begins its descent to the airport, it is 3900 feet from the ground. Its angle of descent is 6 degrees.

a) what is the plane's ground distance to the airport?

b) how far must the plane fly to reach the runway?

Mar 7, 2018

#1
+7616
+2

Point  A  is the current location of the plane.

Point  B  is the point on the ground directly under the plane.

Point  C  is the location of the airport.

m∠BAC   =   90° - 6°   =   84°

a)

plane's ground distance to the airport =  BC

tan 84°  =   BC / AB

tan 84°  =   BC / 3900

3900 tan 84°  =  BC

BC  ≈  37106.021    feet

b)

distance between plane and runway   =   AC

cos 84°   =   AB / AC

cos 84°   =   3900 / AC

AC cos 84°  =  3900

AC  =  3900 / cos 84°

AC  ≈  37310.412    feet

Mar 7, 2018

#1
+7616
+2

Point  A  is the current location of the plane.

Point  B  is the point on the ground directly under the plane.

Point  C  is the location of the airport.

m∠BAC   =   90° - 6°   =   84°

a)

plane's ground distance to the airport =  BC

tan 84°  =   BC / AB

tan 84°  =   BC / 3900

3900 tan 84°  =  BC

BC  ≈  37106.021    feet

b)

distance between plane and runway   =   AC

cos 84°   =   AB / AC

cos 84°   =   3900 / AC

AC cos 84°  =  3900

AC  =  3900 / cos 84°

AC  ≈  37310.412    feet

hectictar Mar 7, 2018