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Find the length of a rectangle given that the perimeter is 110 cm and the length is 1cm more than twice the width.

 Feb 7, 2020
 #1
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+1

Let the length be x+1

Then the width is 2x

The perimeter of the rectangle is 2*(Length + width)

2*(x+1+2x)=2*(3x+1)=6x+2

Given perimeter is 110 cm 

Thus,

6x+2=110

6x=108

x=18

Length is x+1 

x is 18 then length is 19

Width is 2x, then  2(18)=36

Length is 19 and width is 36 cm

How to check?

Given Length is 1cm more than twice the width

Then width is half of 36 which is 18... and since the length is 19 then it is more by 1cm! 

 Feb 7, 2020
 #3
avatar+345 
+1

Hello guest,

If the width is  x = 18  then the length is  2 * x + 1   wink

Dragan  Feb 7, 2020
 #2
avatar+345 
+1

Find the length of a rectangle given that the perimeter is 110 cm and the length is 1cm more than twice the width.

 

110 - 2 = 108

108 / 6 = 18

The width    a = 18 cm

The length   b = 2 * 18 + 1         b = 37 cm    indecision

 Feb 7, 2020

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