Find the length of a rectangle given that the perimeter is 110 cm and the length is 1cm more than twice the width.
Let the length be x+1
Then the width is 2x
The perimeter of the rectangle is 2*(Length + width)
2*(x+1+2x)=2*(3x+1)=6x+2
Given perimeter is 110 cm
Thus,
6x+2=110
6x=108
x=18
Length is x+1
x is 18 then length is 19
Width is 2x, then 2(18)=36
Length is 19 and width is 36 cm
How to check?
Given Length is 1cm more than twice the width
Then width is half of 36 which is 18... and since the length is 19 then it is more by 1cm!
