We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
94
2
avatar+1195 

If a, b, and c are integers satisfying \(a + \frac 1b = \frac{22}{7}\), \(b + \frac 1c = 8\), and abc = 21, then find \(c + \frac 1a\). Express your answer as a common fraction.

 Oct 9, 2019
 #1
avatar+8733 
+2

If a, b, and c are integers satisfying , , and abc = 21, then find . Express your answer as a common fraction.

 

\(\{a,b,c\}\subset \{1,3,7\}\ |abc=21\)

laugh  !

Sorry. Assignment incorrectly written off.

crying

 Oct 9, 2019
edited by asinus  Oct 10, 2019
 #2
avatar+105484 
+3

We can solve this by inspection. Logic

 

If  abc  =  21     and    a + 1/b  =  22/7

 

Then this implies that

 

a + 1/b  =  3  + 1/7

 

Which implies that  a  = 3    and  b  = 7

 

So

 

abc  =21

 

(3)(7)(1)  = 21

 

So  c  = 1

 

And

 

c + 1/a  =    1   + 1/3

 

 

 

cool cool cool

 Oct 10, 2019

16 Online Users

avatar
avatar
avatar