At the zoo, the Spencer family bought 3 adult tickets and 2 children's tickets for $23.50. The Yang family bought 2 adult tickets and 4 children's tickets for $25. How much would the Diaz family spend if they bought 3 adults tickets and 1 children's ticket?
+220 a = cost of adult tickets
c = cost of children's tickets
3a + 2c = 2350
2a + 4c = 2500.
6a+4c = 4700
2a+4c = 2500
4a = 2200
a = 550 or $5.50
3(550) + 2c = 2350
1650 + 2c = 2350
2c = 700
c = 350 or $3.50
The Diaz family's spendings is 3a + c = 3(550) + 350 = 1650+350 = 2000 or $20
+220 a = cost of adult tickets
c = cost of children's tickets
3a + 2c = 2350
2a + 4c = 2500.
6a+4c = 4700
2a+4c = 2500
4a = 2200
a = 550 or $5.50
3(550) + 2c = 2350
1650 + 2c = 2350
2c = 700
c = 350 or $3.50
The Diaz family's spendings is 3a + c = 3(550) + 350 = 1650+350 = 2000 or $20
