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Let be a four-digit number whose square root is three times the sum of the digits of n. Compute n

 Jul 6, 2021
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The logical starting point  is  to look  at  the  4  digit perfect squares where  the  square root is a multiple of 3

 

We find ( through a little trial and error)

 

54^2   =  2916 =  n

 

2 + 9  + 1 +  6 =    18

 

18*3    = 54

 

 

 

cool cool cool

 Jul 6, 2021

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