Let n be a four-digit number whose square root is three times the sum of the digits of n. Compute n
The logical starting point is to look at the 4 digit perfect squares where the square root is a multiple of 3
We find ( through a little trial and error)
54^2 = 2916 = n
2 + 9 + 1 + 6 = 18
18*3 = 54
