Find all the values of x such that 4x−53x+5≥3.
Keep in mind that an equality can be solved like an equation. The only difference is that whenever we multiply or divide by a negative number, we have to switch the greater than or equal to sign to a less than or equal to sign.
We multiply both sides by 3x+5 to get rid of the denominator and get: 4x−5≥3(3x+5).
We then expand out the right hand side: 4x−5≥9x+15.
We subtract and add terms to get all the constants (numbers) on one side and all the variables on the other: −20≥5x.
Finally, we divide by 5 to get x by itself: −4≥x.
