What is the shortest distance from the origin to the circle defined by x^2 - 24x + y^2 + 16y + 160 = 0?
+336 x^2-24x+144)+(y^2+10y+25)=9
(x-12)^2+(y+5)^2=9
(x-12)^2+(y+5)^2=3^2
so the center of the circle is (12,-5)
Using the pythagorean theorem, you would get 12^2+5^2=169
The square root of 169 is 13, so your answer might be 13
Im pretty sure thats your answer Hopefully you understand if not just ask and I'll go more in debt!
