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What is the shortest distance from the origin to the circle defined by x^2 - 24x + y^2 + 16y + 160 = 0?

 Dec 31, 2020
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x^2-24x+144)+(y^2+10y+25)=9

(x-12)^2+(y+5)^2=9

(x-12)^2+(y+5)^2=3^2

 

so the center of the circle is (12,-5)

 

Using the pythagorean theorem, you would get 12^2+5^2=169

 

The square root of 169 is 13, so your answer might be 13 

Im pretty sure thats your answer Hopefully you understand if not just ask and I'll go more in debt!

 Jan 1, 2021

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