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a frame painting has an overall dimension of 32" x 29" 

area of painting alone is 550 square inches. what is the width of frame??

 Nov 27, 2018

Best Answer 

 #2
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Square area of the whole framed picture = 32 x 29 = 928 in^2

928-550 = 378 in^2  = area of frame

 

32 x 29 -( (32-x) (29-x)) = area of frame= 378 in^2    where x = 2 times the width of the frame

928 - x^2 + 61x - 928 = 378

-x^2+61x-378 = 0     Use Quadratic Formula to find x = 54 or 7    (54 is too big...toss it out)

x = 7     width = 1/2 x = 3.5 inches

 

As a check....does the inside dimension of the frame = the picture size of 550 in^2 ?

(32-7)(29-7) = 550     Check!

 Nov 27, 2018
 #1
avatar+20239 
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Back in a few....making corrections to my calcs..

 Nov 27, 2018
edited by ElectricPavlov  Nov 27, 2018
 #2
avatar+20239 
0
Best Answer

Square area of the whole framed picture = 32 x 29 = 928 in^2

928-550 = 378 in^2  = area of frame

 

32 x 29 -( (32-x) (29-x)) = area of frame= 378 in^2    where x = 2 times the width of the frame

928 - x^2 + 61x - 928 = 378

-x^2+61x-378 = 0     Use Quadratic Formula to find x = 54 or 7    (54 is too big...toss it out)

x = 7     width = 1/2 x = 3.5 inches

 

As a check....does the inside dimension of the frame = the picture size of 550 in^2 ?

(32-7)(29-7) = 550     Check!

ElectricPavlov  Nov 27, 2018

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